[最も好ましい] x^2-y^2=2 339795-X^2+(y-2)^2=1
3 Answers The trivial inequality a 2 ≥ 0 is true for any a Im particular, it must be true that But, ( x − y) 2 = x 2 − 2 x y y 2 Therefore, the result follows which yields the result InSince x2 y2 = 21 ((xy)2 (x −y)2) the minimum comes when ∣x−y∣ is smallest, that is 1 if x y is odd Thus, the minimum is 21 ((xy)2 1) More Items Share Copied to clipboardContact Pro Premium Expert Support » Give us your feedback » Surfaces X^2+(y-2)^2=1